John is 5 years older than Mary. In 10 years, twice John's age decreased by Mary's age is 35, and John's age will be twice Mary's current age. Find their ages now.
If x is Mary's age now and yis John's age now, which system of equations could not be used to solve the problem?

Hope this helps

Brainlest please?

Step-by-step explanation:

j=m+5, 2(j+10)-(m+10)=35

So number 2. is the correct answer...

Use the value of j=m+5 in the second equation to get:

2(m+5+10)-m-10=35

2m+30-m-10=35

m+20=35

m=15, and j=m+5=20

So Mary is currently 15 years old and John is 20 years old.

M=15

J=20

Step-by-step explanation:

Let J and M be the present age of John and Mary respectively:

J=M+5

2(J+10)−(M+10)=35

2(M+5+10)−(M+10)=35

2M+30−M−10=35

M=15

J=20

- 1.613 = -1.6 or -1.61

-1.522 = -1.5 or -1.52

0.587 = 0.6 or 0.59

3.079 = 3.1 or 3.08

you already gave the answer

step-by-step explanation: