In ΔMNO, the measure of ∠O=90°, the measure of ∠N=48°, and NO = 73 feet. Find the length of MN to the nearest tenth of a foot.

109.1 feet

Step-by-step explanation:

What function uses the ADJACENT and the HYPOTENUSE?

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\cos N = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{73}{x}

cosN=

hypotenuse

adjacent

​

=

x

73

​

\cos 48=\frac{73}{x}

cos48=

x

73

​

x\cos 48=73

xcos48=73

Cross multiply.

\frac{x\cos 48}{\cos 48}=\frac{73}{\cos 48}

cos48

xcos48

​

=

cos48

73

​

Divide each side by cos 48.

x=\frac{73}{\cos 48}=109.0968\approx 109.1\text{ feet}

x=

cos48

73

​

=109.0968≈109.1 feet

Type into calculator and roundto the nearest tenth of a foot.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116