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Mathematics, 04.03.2021 17:30 snalezinski2509

The first one is done and the options for number four are: w(2w+12)=160
2w^2+12w-260=0
2w^2+12w=260
w^2+6w-130=0


The first one is done and the options for number four are:

w(2w+12)=160
2w^2+12w-260=0
2w^2+12w=2

ansver
Answers: 3

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The first one is done and the options for number four are: w(2w+12)=160
2w^2+12w-260=0
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