The proof A ABC = ADCB that is shown. Given: ZA = 2D; CDAB
Prove: AABC = ADCB
What is the missing reason in the proof?
Statement
Reason
1. ZA ZD
1. given
2. CD||AB
2. given
3. CBBC
3. refl. prop
4. ZABC a ZDCB 4. alt. int. Zs are =
5. ABC = ADCB 5. ?
C
A
D
alt. ext. Zs are
ASA
AAS
corr. int. Zs are
B
B

answer:  

123455421

step-by-step explanation: easy

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation:

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!