Mathematics, 05.03.2021 22:50 edginutystudent
The figure below shows a square ABCD and an equilateral triangle DPC: ABCD is a square. P is a point inside the square. Straight lines join points A and P, B and P, D and P, and C and P. Triangle D Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC: Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60° Triangles APD and BPC are congruent SAS postulate What is the error in Ted's proof?
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The figure below shows a square ABCD and an equilateral triangle DPC: ABCD is a square. P is a point...
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