The size of a TV is determined by the length of the diagonal of the TV. A 42" TV means the length from one corner to the other is 42 inches. If the diagonal forms a 30 degree angle with the base of the TV, what are the height and width of the TV? *

length = 5.38 feet

Step-by-step explanation:

All the eq. can be solved by Phythagoras's theorem

1) Diagonal is 70 inches, height is 42 inches so

70^2 = 42^2 + width^2

width ^2 = 3136, width = 56 inches

2) Base is 2 ft, length of ladder = hypotenuse = 10 ft

Height^2 = 10^2 -2^2 = 96

Height = 9.8 ft

3) Equilateral triangle has a side of 6

If you drop a vertical line from one corner of triangle to opposite side it bisects the side into equal parts. So the length of base is 3

The hypotenuse is 6

So height is sqrt (6*6 -3*3) = sqrt (27) = 3sqrt(3) = 5.2

4) Height = 12, width = 5

Diagonal^2 = 12*12 + 5*5 = 169

Diagonal = 13

5) Plant is 5 ft tall, distance from the ground is 2 ft

length ^2 = 5*5 + 2*2 = 29

length = 5.38 feet

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

40 minutes

step-by-step explanation:

add the time and multiply by 2