Mathematics, 06.03.2021 03:50 cathydaves
Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct?
Jesse
100x^2−100=(10x)^2−10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)
Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)
Answers: 3
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Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct?
Jesse<...
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