Find 3 numbers in GP whose sum is 28 and product is 512​

4,8 and 16

Let the three numbers be a,ar, ar^2 ,

where r is the common ratio.

⇒a+ar+ar^2 =28 and a^3 r^3 =512

⇒ar=8⇒a+ar^2 =20

⇒8r^2 −20r+8=0

⇒r=2,r= 1/2

If r=2,a=4

Therefore, the three numbers are 4,8,16.

Step-by-step explanation:

Hope it is helpful

Where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis. to write an equation in slope-intercept form, given a graph of that equation, pick two points on the line and use them to find the slope. this is the value of m in the equation.