Mathematics, 09.03.2021 21:40 jefarmjefarm9659
Camille buys a cake for $\$24.99$ . She also buys $12$ brownies. Each brownie costs the same amount. She spends $\$39.99$ on the cake and the brownies. Camille finds the cost of each brownie by calculating $(39.99\ -\ 24.99)\ \div\ 12$ . Tanya finds the cost of each brownie by solving the equation $39.99\ +\ 12b\ =\ 24.99$ , where $b$ is the cost of each brownie. Which approach uses the sequence of operations necessary to find the cost of each brownie: Camille’s, Tanya’s, both, or neither? Explain why. Respond in the space provided.
Answers: 2
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Camille buys a cake for $\$24.99$ . She also buys $12$ brownies. Each brownie costs the same amount....
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