Sketch the region bounded by the curves ... y=e^(-x^2), y=0, x=-1, and x=1. Then, rotate this region about the line y=-1 to construct a solid of revolution.

Next, set up an integral to determine the volume of this solid of revolution. (Use the equation Integral from a to b (pi[outer radius]^2 - pi[inner radius]^2) dx

Finally, set up an integral to determine the surface area for this solid of revolution. (Use the equation Integral from a to b (2pi(radius)(sqrt(1+(dy/dx)^2) dx.

I am not sure if I have the right answers! Please help ASAP!