HELP ME PLEASE The straight line L, has equation y=3x-4
The straight line 1, in perpendicular to L, and passes through the point (9.5)
Find an equation of line L

y = -1/3 x + 32/3

Step-by-step explanation:

Find an equation of line L

Given the equation bog L1 as y ,= 3x-4

The slope of the line L1 is 3

Since both lines are perpendicular, the product of their slope is -1, hence ;

LL1 =-1

3L = -1

L = -1/3

Slope of the required line is -1/3

Get the equation in point lope form

y-y0 = m(x-x0)

y-9 = -1/3(x-5)

3(y-9) = -(x-5)

3y-27 = -x+5

3y = -x+5+27

3y = -x+32

y = -1/3 x + 32/3

This gives the required equation

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5

it would be 3 ÷by 6 because the number on each side