This is a tough one that I solved, I wanted to see how everyone else solves it. take your time, I don't need an answer straight away because I solved it... and made it.

14+y+x+z+a+b+c=1203

x=z+23

z=a+102

a=b-42+c

b=c+82

c=y+20

a=2c+40 z=2c+142 x=2c+165 b=c+82 y=c-20

14+2c+40+2c+142+2c+165+c+82+c-20=1203

c=86 2/3

y=66 2/3

b=168 2/3

x=338 1/3

z=315 1/3

a=213 1/3

22

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.