The equation for the motion of an object with constant acceleration is d = vt + 0.5at where dis distance traveled in ft, v is starting velocity in ft / s , a is acceleration in t / (s ^ 2) and t is time in seconds . A racecar begins with a velocity of 200ft / s and accelerates at 100ft / (s ^ 2) Write an expression for the distance the car travels after t seconds .

step-by-step explanation:

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)