What is the equation of the line that passes through the point (–2,1) and has a slope of
3/2

y = x + 4

Step-by-step explanation:

Find b and substitute for y = mx + b so

1 = 3/2(-2) + b

1 = -3 + b, so b = 1+3, b=4

Put it all together y = x + 4

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

i think the answer is d im not sure