The vertices of AABC are A(-4,4), B(-2,2), and C(-5,2). If AABC is reflected across the line y=1 to produce the image AA'B'C', find the coordinates of the vertex B'.
The coordinates of B' after a reflection across the line y = 1 are
(Type an ordered pair.)
1

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94