A December 2017 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a greater proportion of students at your school use the internet that much. You take a random sample of 60 students and find that 36 of them use the internet for an hour or more each day. Assume your school has more than 600 students. You will test the hypotheses He :p=0.43; H. -p > 043, where p = the true proportion of students at your school who use the internet for an hour or more each day. Which of the following gives the correct test statistic for this test? a.

0.6 - 0.43
2 =
[0.43) (0.57)
60

0.6 -0.43
2 =
(0.6) (0.4)
60

0.43 -0.6
z =
(0.6) (0.4)
60

36 -60
(36) (24)
60

0.43 -0.6
(0.6)(0.4)
600

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

if she was to only spend a dollar she can get 1lb

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt