A circle with radius 2 units passes through the center A of another circle and intersects it at points B and C. Points A, B, and C divide the circumference of the smaller circle into 3 equal parts. One-tenth of the area of the smaller circle is outside of the bigger circle. What part of the area of the bigger circle is covered by the smaller circle?

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

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