PLZ HELP Find the equation of the graphed line.
On a coordinate plane, a line goes through (0, 5) and (2, 0).
a.
y = negative 2 x + 5
c.
y = 2 x + 5
b.
y = negative two-fifths x + 2
d.
y = negative five-halves x + 5

d. -5/2x + 5 (negative five-halves x + 5)

Step-by-step explanation:

In order to find the equation for the line that passes through these points, you must identify the slope and y-intercept. You can find the slope by finding the change in y divided by the change in x:

using (0, 5) and (2, 0),

change in y = 5

change in x = -2

(change in y)/(change in x) = -5/2

So, the slope is -5/2. You don't need to calculate the y-intercept since one of the points already is the y-intercept; when x is 0, y is 5, so the y-intercept is 5. Now, you can write your equation:

using y = mx + b, where m = slope and b = y-intercept,

y = -5/2x + 5

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

47 - 90 = 43

43 - 180 = x

x = 137