Write an equation of the line that passes through the points (3,8) and (2.6). Write the equation in slope-intercept form. The equation of the line in slope-intercept form is

2x - y + 2 = 0 is the equation

y = 2x + 2 is the equation in slope-intercept form

Step-by-step explanation:

slope = (y₂ - y₁) / (x₂ - x₁)

slope = (6 - 8) / (2 - 3)

slope = -2 / -1

slope (m) = 2

equation through the points (3,8) and (2,6):

(y - y₁) / (y₂ - y₁) = (x - x₁) / (x₂ - x₁)

(y - 8) / (6 - 8) = (x - 3) / (2 - 3)

(y - 8) / -2 = (x - 3) / -1

-y + 8 = -2x + 6

2x - y + 2 = 0

slope-intercept form,

y = mx + c

y = 2x + 2

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

i don't think there is enough