If B is the midpoint of AC, AB = 8x + 5, and BC = 5x2 - 16, then find x and AC

Step-by-step explanation:

AB = 8x + 5

BC = 5x² - 16

5x² -  16 = 8x + 5

5x² - 8x - 21 = 0

Quadratic formula

x = [8 ± √(8² – 4·5(-21))] / [2·5]

 = [8 ± √484] / 10

 = [8 ± 22] /10

 = -1.4, 3

-1.4 is an extraneous solution.

x = 3

AB = 8x+5 = 29

AC = 58

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20