Trying to help my daughter can't figure this out. The perimeter of a rectangle is 72 inches. The width of the rectangle is 4meters less than the length. Find the length and width of the rectangle. (use l for the length)​

length = 20m

width = 16m

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

Firstly, I would assume that you made a unit error for the perimeter, which I would believe is meters.

With that, we can now make these statements:

Perimeter = 72m

Perimeter = 2l + 2w

therefore,

2l + 2w = 72

Since the question states the width is 4 meters less than the length, we can make this statement,

w = l - 4

We can now substitute this into the first statement we made, 2l + 2w = 72

2l + 2(l - 4) = 72

2l + 2l - 8 = 72

4l - 8 = 72

4l = 80

l = 20m

Using the second statement, w = l - 4, we can now find w,

w = 20 - 4

w = 16m

Therefore, the length is 20m and the width is 16m

darn right!

step-by-step explanation:

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