You invested S3000 between two accounts paying 4% and 8% annual interest respectively if the total interest eamed for the year was S520 how much was invested at each ratė? was invested at 4% and so was invested at se​

Even investing the $ 3,000 in the account at 8%, the result would be an annual interest of $ 240, with which there is an error in the wording of the question.

Step-by-step explanation:

Given that you invested $ 3000 between two accounts paying 4% and 8% annual interest respectively, to determine how much was invested at each rate if the total interest eamed for the year was $ 520, the following calculation must be performed:

3000 x 0.04 + 0 x 0.08 = 120

1500 x 0.04 + 1500 x 0.08 = 180

3000 x 0.08 + 0 x 0.04 = 240

Thus, as can be seen, even investing the $ 3,000 in the account at 8%, the result would be an annual interest of $ 240, with which there is an error in the wording of the question.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c