Can someone please help me please !

Step-by-step explanation:

GH : √(8-4)^2 + (2-5)^2 = √16+9 = √25 = 5

HI : √(-6-2)^2 + (2-8)^2 = √64+36 = √100 = 10

IJ : √(-2-2)^2 + (-3+6)^2 = √16 + 9 = √25 = 5

JH : √(-2-4)^2 + (-3-5)^2 = √36 + 64 = √100 = 10

Slope of the line that contains GH

(2-5)/(8-4) = -3/4

Slope of the line that contains HI

(-6-2) / (2-8) = 8/6 = 4/3

I calculated the distance between points. Thanks to that I noticed that the opposite sides are congruent, so the quadrilateral can be a rectangle or a parallelogram. So I found the slope of the lines that contain two consecutive sides and I discovered that are perpendicular. So the quadrilateral is a rectangle because its angles are all of 90 degrees

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.