Which sequence of two transformations maps ABC to A'B'C? ☁︎
a: a rotation 90° counterclockwise about the origin, then a reflection over the line y= -x
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b:A translation 7 units to the right then a reflection over the x-axis
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c:A rotation 90° clockwise about the origin, then a reflection over the x-axis
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d:A reflection over the y -axis , then a translation 8 units down
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Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Divide. write in the simplest form. 4 1/6 divided by 10

Candy lives in the center of town. her friend darlene lives 28 miles to the east and her friend dana lives 21 miles north. approximately how far do dana and darline live apart ?