a toy rocket is launched from the top of a 48 foot hill. the rockets initial upward velocity is 32 feet per second and its hight(h) at any given second(t) is modeled by the equation x=-16t^2+32t+48 how long was the rocket in the air, how high was the rocket at 2 seconds, how high did the rocket go

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )

The answer is 4 points