What is the area of a triangle whose vertices are r(−4,2) r ( − 4 , 2 ) , s(1,2) s ( 1 , 2 ) , and t(−5,−4)

The area of that triangle would be 5 units².
The formula for the area of a triangle is 1/2bh; with b being base and h being the height.
The base of the triangle is length of segment TS which is 5 units
The height of the triangle is 4-2= 2 units.
5×2=10
10÷2= 5

Idon’t know what the answer is i wish i could