Clayton needs to reflect the triangle below across the line y = x. On a coordinate plane, triangle A B C has points (5.5, 7), (6, 2), (4, 4).

Which statements about the reflection are true? Check all that apply.
Clayton could use the relationship (x, y) right-arrow (y, x) to find the points of the image.
Clayton could negate both the x and y values in the points to find the points of the image.
C’ will remain in the same location as C because it is on the line of reflection.
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles.
The image and pre-image will not have the same orientation because reflections flip figures.

A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.

C. C’ will remain in the same location as C because it is on the line of reflection.

D. The image and the pre-image will be congruent triangles.

Step-by-step explanation:

A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.

This option is TRUE. When we reflect a shape in the line y=xy=x , we just have to swap the x and y coordinates.

B. .Clayton could negate both the x and y values in the points to find the points of the image.

False; This is a rotation of 180\degree180° about the origin.

C. C’ will remain in the same location as C because it is on the line of reflection.

This statement is True

C’ will move because all points move in a reflection.

This statement is false because,C(2,2) and C'(2,2) will have the same coordinate.

D. The image and the pre-image will be congruent triangles.

This is TRUE because reflection is a shape preserving transformation(rigid motion).

E. The image and pre-image will not have the same orientation because reflections flip figures.

This is False

A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.

C. C’ will remain in the same location as C because it is on the line of reflection.

D. The image and the pre-image will be congruent triangles.

Step-by-step explanation:

A. Clayton could use the relationship (x,y)\rightarrow (y,x)(x,y)→(y,x) to find the points of the image.

This option is TRUE. When we reflect a shape in the line y=xy=x , we just have to swap the x and y coordinates.

B. .Clayton could negate both the x and y values in the points to find the points of the image.

False; This is a rotation of 180\degree180° about the origin.

C. C’ will remain in the same location as C because it is on the line of reflection.

This statement is True

C’ will move because all points move in a reflection.

This statement is false because,C(2,2) and C'(2,2) will have the same coordinate.

D. The image and the pre-image will be congruent triangles.

This is TRUE because reflection is a shape preserving transformation(rigid motion).

E. The image and pre-image will not have the same orientation because reflections flip figures.

This is False

Hope this helps :)

Step-by-step explanation:

abde or 1,2,4, 5 is the answer

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.