Find the area of triangle ABC and the area of XYZ. AABC - AXYZ.

ABC= 60 XYZ=540

Step-by-step explanation:

The area of a triangle is 1/2*base*height so for ABC we need to find the height first. To do this we use pythag theorem, and create the equation 13^2=5^2+height^2 rearranging this we can figure out that sqrt(height)=13^2-5^2. For the base we do 2*5 since there are two congruent line segments both equal to 5. Using this we can do 1/2*12*10=area of ABC

For XYZ we can do 1/2*30*36=area of XYZ, we can do 2*15 since there are 2 congruent 15 length line segments at the base.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c