Two different formulas of an oxygenated motor fuel are being tested to study their road octane numbers. The variance of road octane number for formula 1 is and for formula 2 it is Two random samples of size and are tested, and the mean octane numbers observed are fluid ounces and fluid ounces. Assume normality. (a) Test the hypotheses H_0: mu_1 = m_2 = m_2 versus H_1:mu_1 < mu_2 versus H_1: mu_1 < mu_2 using alpha = 0.05. (e. g. 98.765). z_0 = H_0.
(b) Calculate a 95% two-sided confidence interval on the mean difference road octane number, X bar_1 - X bar _2. (e. g. 98.765). lessthanorequalto mu_1 - mu_2 lessthanorequalto
(c) what sample size would be required in each population if you wanted to be 95% confident that the error in estimating the difference in mean road octane number is less than 1? N_1 = n_2 =. Round your answer up to the nearest integer.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: