Write the equation of the line that is perpendicular to 4x - 3y = 6 and passes through (4, -2)

Perpendicular is slope multiplies to -1
for
ax+by=c
slope=-a/b

4x-3y=6
-a/b=-4/-3=4/3
perpendicular to 4/3 is -3/4

point slope form
y-y1=m(x-x1)
for slope=m
a point is (x1,y1)

point (4,-2)
slope is -3/4
y-(-2)=-3/4(x-4)
y+2=-3/4(x-4)
or converted
y=-3/4x+1
or
3x+4y=4

I’m pretty sure the slope would be 1 since the x and y values increase by 1