1) a2 - 12a + 35

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(a−5)(a−7)

Step-by-step explanation:

factor a2−12a+35

a2−12a+35

The middle number is -12 and the last number is 35.

Factoring means we want something like

(a+_)(a+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -12

Multiply together to get 35

Can you think of the two numbers?

Try -5 and -7:

-5+-7 = -12

-5*-7 = 35

Fill in the blanks in

(a+_)(a+_)

with -5 and -7 to get...

(a-5)(a-7)

bdhfnfhjffjkfjfjfjjf

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.