Suppose the depth of the tide in a certain harbor can be modeled by y = 23 - 5 cos la wh
where y is the water depth in feet
and t is the time in hours. Consider a day in which t = 0 represents 12:00 midnight. For that day, when are high tide and
low tide and what is the depth of each?

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

351.23

step-by-step explanation:

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.