1. Write the balanced chemical equation for the reaction you are performing. 4. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial. • Trial 1:
• Trial 2:

5. Determine the percent yield of MgO for your experiment for each trial.
• Trial 1:
• Trial 2:
6. Determine the average percent yield of MgO for the two trials.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

37 = ending with 7

unit's digit in the cube..3

56 = ending with 6

unit's digit in the cube..2

133 = ending with

unit's digit in the cube..7

hope it : ( : )