Larry is 4 times as old as his niece. Four years ago he was 6 times as old as his niece was then. Find each of their ages now

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Step-by-step explanation:

Let n represent the current age of the niece. Then 4n is Larry's current age. 4 years ago, the relationship was ...

  6(n -4) = 4n -4

  6n -24 = 4n -4

  2n = 20

  n = 10

Larry is 40; his niece is 10.

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: