(The one about the ship is what I need the answers for) A ship drops anchor in a harbor. The anchor is 56 feet above the surface
of the water before it is released. To solve the following problems, you
will have to determine the
equation to this situation.
After how much time, in seconds,
will the anchor reach the surface of
the water?
Approximately long in seconds, into
the anchor's release, will the anchor
be only 16 feet above the surface of
the water?
III
At what height, in feet above the
surface of the water, will the anchor
be after 1.5 seconds of release?

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )