A polynominak function has a root of -6 with a multiplicity 1, a root if -2 with a multiplicity of 3, a root if 0 with a multiplicity of 2, a root if 4 with a multiplicity of 3. if the function has a posative leading coefficient and is of odd degree, which statement about the graph is true? a. the graph of the function is positive on (-6,-2)
b the graph of the function is negative on (-infinity symbol, 0)
c. the graph of the function is positive on (-2,4)
d. the graph of the function is negative on (4, infinity symbol).
​

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

answer: 193

explanation:

200-7 = 193