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Given:

Endpoints of a line segment EF are E(-3,8) and F(7,-7).

Point  P divides the segment EF such that EP:PF = 2:3.

To find:

The coordinates of the point P.

Solution:

Section formula: If a point divides a line segment in m:n, then the coordinates of the points are:

It is given that EP:PF = 2:3. It means the point P divides the segment EF in 2:3.

Using section formula, we get

Therefore, the coordinates of the point P are (1,2).

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

step-by-step explanation:

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