Mathematics, 15.04.2021 23:40 nook4boo

AB and CD are straight line segments. ∠ AOE = 50° and ∠ DOB = 95°.
Find the values of the following angles giving a reason for each answer in the comment box.
The diagram is not drawn accurately.
i) obtuse ∠ AOC
ii) acute ∠ BOC
iii) acute ∠ DOE

AB and CD are straight line segments.

∠ AOE = 50° and ∠ DOB = 95°.
Find the values of the followi

Answers: 2

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Answer from: deojahnaeb37

i) Angle AOC is 95° Reason:- Angle AOC is equal to Angle DOB since they are Vertically Opposite Angles. ii) Angle BOC is 85° Reason:- Angle AOC + Angle BOC - 180° (they lie in a straight line so they are a linear pair. Sum of the angles will be 180°) Angle AOC is 95°, So:- 95° + Angle BOC = 180° Angle BOC= 180° - 95° Angle BOC = 85° iii) Angle DOE is 17° Reason:- Angle AOE+ Angle DOE+ Angle DOB = 180° (they lie in a straight line so they're a linear pair. Sum of the angles will be 180°) So, 68° + Angle DOE+ 95° = 180° 163° + Angle DOE = 180° Angle DOE= 180° - 163° Angle DOE is 17°

Answer from: Quest

well the answer to that is xoxoxo

step-by-step explanation:

Answer from: Quest

Answer: f(x) = -2x^3 +3x^2 +11x -6see attachedan infinite number. since the magnitude of the leading coefficient is not specified, it may be any negative number. (we have chosen the smallest magnitude integer that makes all coefficients be integers.)step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

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AB and CD are straight line segments. ∠ AOE = 50° and ∠ DOB = 95°.
Find the values of the fol...

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