What is the factorization of 2x2 + 5x + 3? O A. (2x+3)(x + 1)
O B. (2x + 3)(x + 3)
O C. (x+3)(x + 3)
O D. (x+3)(x + 1)
Help ASAP!

(2x+3)(x + 1)

Step-by-step explanation:\

Since the first term has a coefficient, multiply 3 by 2 which results in 6.

Now to break the equation into groups, we have to find two integers that have a product of 6 and a sum of 5. The two integers are 2 and 3.

2x² + 5x + 3

= (2x² + 2x) + (3x + 3)

Factor out the GCF.

2x (x + 1) + 3(x + 1)

Divide the whole equation by x+1.

Now you're left with (x + 1) and (2x+3)

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =