An engineer is proof-reading his report and finds that he has mistakenly used micrometers as a unit of measure. His experiment showed a
measurement of 2 micrometers, but the government requires the
measurement to be in millimeters. How should the engineer record the
measurement (if there are 1000 micrometers in 1 millimeter)? *

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

step-by-step explanation:

this is not a question

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s