If a person shoots a basketball overhand from a position of 8 feet from the floor, then the path of the basketball through the hoop can be modeled by the parabola y=(-16x^2/0.434v^2)+1.15x+8, where v is the velocity of the ball in ft/sec, y is the height of the hoop and x is the distance away from the hoop. if the basketball hoop is 10 feet high and located 17 feet away, what initial velocity v should the basketball have to go through the hoop?

The initial velocity of ball should be 0.0406 ft/s.

Step-by-step explanation:

x = the distance away from the hoop

y =  Height of the hoop

v =  velocity of the ball

Given : x = 17 ft, y = 10 ft , v = ?

v = 0.0406 ft/s

The initial velocity of ball should be 0.0406 ft/s.

14

step-by-step explanation:

14 x 3 = 42

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation: