Which of the following statements have the same result? explain each step in solving each one.
i. f(2) when f(x) = 3x + 2
ii. f-1(3) when f(x) = 2 x minus 7, all over 3
iii.2y + 14 = 4y - 2

First:   f(2) is same as  f(x=2) so all we have to do is to express x=2 in f(x)
f(2) = 3*2 + 2 = 8

Second
 f^(-1) (3) is inverse function.  first we solve f(x) for x.
let f(x) be equal to some variable m
m = (2x -7)/3
3m = 2x - 7
2x = 3m + 7
x = (3m + 7)/3
now we write:
f^-1(x) = (3x + 7)/3

x=3
f^-1(3) = 16/3

Third
  2y + 14 = 4y - 2
      we just solve for y
     2y = 16
      y = 8

Now we take that f(x) = y because we both write to be the functions of x

that means that First and third have same result.