Geometry
three of the labeled points are chosen at random. what is the probability that they are collinear?

The solution to the problem is as follows:

There are (5/3) = 10 sets of three points.

There are 2 sets which are collinear: EDC, and EAB

Therefore: P ( 3 points collinear ) = 2/10 = 1/5

I hope my answer has come to your help. God bless and have a nice day ahead!

Hello there.

Three of the labeled points are chosen at random. What is the probability that they are collinear?

 1/5

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