Arectangle has an area of x3 + 5x2 + 5x – 2 square meters and a width of x + 2 meters. find its length.

a) x2 + 5x – 4 meters
b) x2 +3x – 1 meters
c) x2 + 7x – 9 meters
d) x2 + 3x + 1 meters

Step-by-step explanation:

Given : Area of rectangle :

            Width :

To Find : Length

Solution :

Formula of area of rectangle :

Substituting the given values in formula to calculate Length.

---(A)

Solving this equation using Formula :

Dividend = (Divisor * Quotient) +Remainder

Since dividend is

Divisor is  

Thus ,

⇒

⇒

⇒

Thus the quotient is

So, A becomes

Hence Length of Rectangle is  

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240