Can someone check my

what is the solution set to x^2 = 6x + 27?

a. (-9, -3)
b. (-3, 9)
c. (9, -3)
d. (3, 9)

my b. (-3, 9)

Minus 6x+27 both sides
x^2-6x-27=0
factor
what 2 numbers multiply to get -27 and add to get -6
-9 and 3
(x-9)(x+3)=0
set to zero
x-9=0
x=9

x+3=0
x=-3

x=9 and -3
C or B is the answer, they are the same, just switched
if there is some new way of doing it, I don't konw
I would pick B

(x) - (y) = (1 + 4i)

(3 + 6i) - (2 + 2i) = (1 + 4i)