What are the first three terms of the sequence represented by the recursive formula an=n^2-an-1 if a5=14 1/4

  1/4, 3 3/4, 5 1/4

Step-by-step explanation:

Solving for a[n-1], we get ...

  a[n-1] = n^2 -a[n]

Then ...

  a[4] = 5^2 -a[5] = 25 -14 1/4 = 10 3/4

  a[3] = 4^2 -a[4] = 16 -10 3/4 = 5 1/4

  a[2] = 3^2 -a[3] = 9 -5 1/4 = 3 3/4

  a[1] = 2^2 -a[2] = 4 -3 3/4 = 1/4

Then the first three terms are a[1], a[2], and a[3]:

  1/4, 3 3/4, 5 1/4

a

step-by-step explanation:

the answer is a

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.