In a certain school, 17 percent of the student are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. what is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course?

The probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course can be solve by: P = F x Psy Where F is the fraction of foreign language Psy is fraction in psychology   P = 0.28 x 0.17 P = 0.0476 is the probability 

yes

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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