3y - 2 = y + 4

what is the value of y? i got 3 from a calculator but i'm having trouble understanding why. could anyone briefly explain how you get this answer?

my attempt is:
3y - 2 = y + 4
+2 +2
3y = y + 6
here is where i get stuck. if you divide, the y value goes away. but you cannot subtract because there is nothing to subtract could someone explain my next step and/or where i am going wrong?

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: