Abullet is fired into the air with an initial velocity of 1600 f/s at an angle for 45 dgrees from the horizontal. what is the horizontal distance traveled by the bullet in 2 seconds?

So you know the horizontal acceleration is zero integrating this you can find the horizontal velocity as vh=Vcos(α) V = initial velocity 1200 ft/sec the angle is 45 so you have vh=1200cos(45) if you integrate this equation with respect to time (t) you get the horizontal displacement equation. the initial condtions for the horizontal displacement seem to bet at t = 0, x = 0 then when you get the equation, just substitute t = 2 and evaluate

B. 16is the absolute value