Consider a pyramid with a height 10 feet in a square base with side lengths 7 feet. how does the volume of the pyramid change if the base stays the same and the height is doubled

The volume of a pyramid is given by the formula

V= 1/3 x bxh
b= base, since the base is square, so b= L²=49 feet²
h=10feet
so finally  V= 1/3x 49x10= 163.33 ft^3

if the height is doubled it means  H=2h=20
so the volume is V= 1/3x 49x 20=326.33 ft^3